A body of 10 kg is acted by a force of 129.4 N if `g=9.8m//sec^2`. The acceleration of the block is `10m//s^(2)`. What is the coefficient of kinetic friction

When the three blocks of masses M, 2M and 2M in the system are released from rest, they accelerate with a magnitude of 1 m/ s^(2) . What is the coefficient of kinetic friction between block on the table and the table top? (neglect the force of friction in the pulleys and take g =10 m/ s^(2) )

A horizontal force of 150N produces an acceleration of 2m/s2 in a body placed on a 6 horizontal surface. A horizontal force of 200N produces an acceleration of 3m//s^2 . The mass of the body and coefficient of kinetic friction are (g = 10 ms^(-2) )

In the figure ( g = 10 m//s^(2) ) .Acceleration of 2kg block is :

A block of mass 5kg is on a rough horizontal surface and is at rest. Now a force of 24 N is imparted to it with negligible impulse. If the coefficient of kinetic friction is 0.4 and g=9.8m//s^(2) , then the acceleration of the block is

A slab of 40 kg lying on a frictionales floor and a block of 10 kg rests on the slab as shown in the figure. The coefficients of static and kinetic friction between the slab and the block are 0.6 and 0.4 respectively. If a force of 100 N is applied on the block, then the acceleration the slab will be (g = 10 m//s^(2))

A slab of 40 kg lying on a frictionales floor and a block of 10 kg rests on the slab as shown in the figure. The coefficients of static and kinetic friction between the slab and the block are 0.6 and 0.4 respectively. If a force of 100 N is applied on the block, then the acceleration the slab will be (g = 10 m//s^(2))