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Find the ratio in which the line x-3y=0 ...

Find the ratio in which the line `x-3y=0` divides the line formed by joining `(-2,-5)` and `(6,3)` .Find the coordinates of the point of intersection

Text Solution

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The correct Answer is:
Let P(x, y) be the point and m:n is the ratio
then `x=(6n-2m)/(m+n),y=(3n-5m)/(m+n)` …………(1)
From equation of line `x=3y rArr (x)/(y)=3`
By putting `x=3y` or `(x)/(y)=3` is (1)
`m:n=3:13`
Then `P(x, y)= ((9)/(2), (3)/(2))`
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