Home
Class 10
MATHS
Find the value of k so that the area of ...

Find the value of k so that the area of the triangle with vertices A(k+1, 1), B(4, -3) and C(7, -k) is 6 square units.

Text Solution

Verified by Experts

The correct Answer is:
K=3
Promotional Banner

Topper's Solved these Questions

  • Co-ordinate Geometry

    CBSE COMPLEMENTARY MATERIAL|Exercise LONG ANSWER TYPE QUESTIONS -III|10 Videos

  • Co-ordinate Geometry

    CBSE COMPLEMENTARY MATERIAL|Exercise PRACTICE-TEST (Coordinate Geometry) SECTION-A|4 Videos

  • Co-ordinate Geometry

    CBSE COMPLEMENTARY MATERIAL|Exercise VERY SHOT ANSWER TYPE QUESTIONS (State True or False)|22 Videos

  • CIRCLES

    CBSE COMPLEMENTARY MATERIAL|Exercise PRACTICE - TEST (SECTION - D)|1 Videos

  • CONSTRUCTIONS

    CBSE COMPLEMENTARY MATERIAL|Exercise (PRACTICE-TEST) SECTION-C|1 Videos

Similar Questions

Explore conceptually related problems

Find the values of k so that the area of the triangle with vertices (1,-1),(-4,2k) and (c ,-5 is 24sq .units.

Area of the triangle having vertices (1,2,3),(2,-1,1) and (1,2,4) in square units is

For what value of k(k gt 0) is the area of the triangle with vertices (-2, 5), (k, -4) and (2k +1, 10) equal to 53 square units?

Find the area of triangle whose vertices are A(6,7),B(2,-9) and C(-4,1)

Find the value of a for which the area of the triangle formed by the points A(a , 2a), B(-2, 6) and C(3, 1) is 10 square units.

Find the value of K if area of the triangle is 4 sq.unit and vertices are (K,0),(4,0) and (0,4)