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In right angled Delta ABC, angle B=90^(@...

In right angled `Delta ABC, angle B=90^(@) and AB=sqrt34` units . The co-ordinares of points B, C are (4. 2) and (-1, y) respectively . If ar ` Delta ABC=17` sq . Units, then find the value of y .

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To solve the problem step by step, we can follow these instructions: ### Step 1: Understand the given information We have a right-angled triangle ABC with: - Angle B = 90 degrees - Length of AB = √34 units - Coordinates of B = (4, 2) - Coordinates of C = (-1, y) - Area of triangle ABC = 17 square units ### Step 2: Use the area formula for a triangle The area of a triangle can be calculated using the formula: \[ \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} \] In this case, we can take BC as the base and AB as the height. Therefore, we can write: \[ \frac{1}{2} \times BC \times AB = 17 \] Substituting the value of AB: \[ \frac{1}{2} \times BC \times \sqrt{34} = 17 \] ### Step 3: Solve for BC Multiplying both sides by 2: \[ BC \times \sqrt{34} = 34 \] Now, divide both sides by √34: \[ BC = \frac{34}{\sqrt{34}} = \sqrt{34} \] ### Step 4: Find the length of BC using the distance formula The distance formula between two points \((x_1, y_1)\) and \((x_2, y_2)\) is given by: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] Applying this to points B (4, 2) and C (-1, y): \[ BC = \sqrt{((-1) - 4)^2 + (y - 2)^2} \] This simplifies to: \[ BC = \sqrt{(-5)^2 + (y - 2)^2} = \sqrt{25 + (y - 2)^2} \] ### Step 5: Set the two expressions for BC equal Now we have two expressions for BC: \[ \sqrt{25 + (y - 2)^2} = \sqrt{34} \] Squaring both sides: \[ 25 + (y - 2)^2 = 34 \] ### Step 6: Solve for y Subtract 25 from both sides: \[ (y - 2)^2 = 9 \] Taking the square root of both sides gives: \[ y - 2 = 3 \quad \text{or} \quad y - 2 = -3 \] Thus: 1. \(y - 2 = 3 \Rightarrow y = 5\) 2. \(y - 2 = -3 \Rightarrow y = -1\) ### Step 7: Conclusion The possible values for y are: \[ y = 5 \quad \text{or} \quad y = -1 \]
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