If the class marks of a continuous frequency distribution are 22, 30, 38, 46, 54, 62 then the class corresponding to class mark 46 is _____

Answer

To find the class corresponding to the class mark of 46 in a continuous frequency distribution, we can follow these steps:

### Step 1: Identify the Class Marks
The given class marks are: 22, 30, 38, 46, 54, 62.

### Step 2: Calculate the Class Interval
To determine the class intervals, we need to find the difference between consecutive class marks.

- Difference between 22 and 30:
\(30 - 22 = 8\)

- Difference between 30 and 38:
\(38 - 30 = 8\)

- Difference between 38 and 46:
\(46 - 38 = 8\)

- Difference between 46 and 54:
\(54 - 46 = 8\)

- Difference between 54 and 62:
\(62 - 54 = 8\)

From the calculations, we can see that the difference between each consecutive class mark is consistently 8.

### Step 3: Determine the Class Intervals
To form the class intervals, we can take each class mark and subtract and add half of the class width (which is 4, since \(8/2 = 4\)):

- For the class mark 22:
- Lower limit: \(22 - 4 = 18\)
- Upper limit: \(22 + 4 = 26\)
- Class interval: \(18 - 26\)

- For the class mark 30:
- Lower limit: \(30 - 4 = 26\)
- Upper limit: \(30 + 4 = 34\)
- Class interval: \(26 - 34\)

- For the class mark 38:
- Lower limit: \(38 - 4 = 34\)
- Upper limit: \(38 + 4 = 42\)
- Class interval: \(34 - 42\)

- For the class mark 46:
- Lower limit: \(46 - 4 = 42\)
- Upper limit: \(46 + 4 = 50\)
- Class interval: \(42 - 50\)

- For the class mark 54:
- Lower limit: \(54 - 4 = 50\)
- Upper limit: \(54 + 4 = 58\)
- Class interval: \(50 - 58\)

- For the class mark 62:
- Lower limit: \(62 - 4 = 58\)
- Upper limit: \(62 + 4 = 66\)
- Class interval: \(58 - 66\)

### Step 4: Identify the Class for Class Mark 46
Now, we look for the class interval that contains the class mark 46. From our calculations, we see that:

- The class interval for the class mark 46 is \(42 - 50\).

### Final Answer
The class corresponding to the class mark 46 is **42 to 50**.

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