10g" of "MnO_(2)" on reaction with "HCl" forms "2.24L" of "Cl_(2)(g)" at "NTP," the percentage impurty of "MnO_(2)" ? "

10g of MnO_(2) on reactoin with HCI forms 2.24 L of Cl_(2)(g) at NTP_(1) the percentage impurity of MnO_(2) is :- MnO_(2)+4HCl to MnCl_(2)+Cl_(2)+2H_(2)O

10g of MnO_(2) on reactoin with HCI forms 2024 L of Cl_(2)(g) at NTP_(1) the percentage impurity of MnO_(2) is :- MnO_(2)+4HCl to MnCl_(2)+Cl_(2)+2H_(2)O

In the following reaction, MnO_(2) + 4HCl rarr MnCl_(2) + 2H_(2)O + Cl_(2) 2 mole MnO_(2) reacts with 4 mol of HCl to form 11.2 L Cl_(2) at STP. Thus, percentage yield of Cl_(2) is:

In the following reaction, MnO_(2) + 4HCl rarr MnCl_(2) + 2H_(2)O + Cl_(2) 2 mole MnO_(2) reacts with 4 mol of HCl to form 11.2 L Cl_(2) at STP. Thus, percentage yield of Cl_(2) is:

10g of pyrolusite on reaction with conc. HCl liberated 0.1 equivalent of Cl_(2) . Percentage purity of pyrolusite sample-

A 0.5 g sample containing MnO_(2) is treated with HCl liberating Cl_(2) is passed into a solution of KI and 30.0 " mL of " 0.1 M Na_(2)S_(2)O_(3) are required to titrate the liberated iodine. Calculate the percentage of MnO_(2) is the sample.

A 0.5 g sample containing MnO_(2) is treated with HCl liberating Cl_(2) is passed into a solution of KI and 30.0 " mL of " 0.1 M Na_(2)S_(2)O_(3) are required to titrate the liberated iodine. Calculate the percentage of MnO_(2) is the sample.