2x^(2)+kx+3=0

If x=-(1)/(2) is a solution of the quadratic equation 3x^(2)+2kx-3=0 , find the velue of k.

If x=-(1)/(2) is a solution of the quadratic equation 3x^(2)+2kx-3=0 , find the velue of k.

In each of the following,determine the value of k for which the given value is a solution of the equation: kx^(2)+2x-3=0,x=2 (ii) 3x^(2)+2kx-3=0,x=-(1)/(2)( iii) x^(2)+2ax-k=0,x=-a

Find the value(s) of k for which the given quadratic equations has real and distinct roots : (i) 2x^(2)+kx+4=0 (ii) 4x^(2)-3kx+1=0 (iii) kx^(2)+6x+1=0 (iv) x^(2)-kx+9=0

Find the value(s) of k for which the given quadratic equations has real and distinct roots : (i) 2x^(2)+kx+4=0 (ii) 4x^(2)-3kx+1=0 (iii) kx^(2)+6x+1=0 (iv) x^(2)-kx+9=0

In the following,determine the set of values of k for which the given quadratic equation has real roots: 3x^(2)+2x+k=0 (ii) 4x^(2)-3kx+1=0 (iii) 2x^(2)+kx-4=0

If the remainder on dividing x^(3) + 2x^(2) + kx + 3 by x - 3 is 21, find the quotient and the value of k. Hence find the zeros of the polynomial x^(3) + 2x^(2) + kx - 18 .

If the equations 2x^(2)+kx-5=0 and x^(2)-3x-4=0 have a common root,then the value of k is

Find the values of k for which the given equation has real roots: (i) kx^(2)-6x-2=0" "(ii)" "3x^(2)+2x+k=0" "(iii)" "2x^(2)+kx+2=0

If the roots of a quadratic equation 2x^(2)+3kx+8=0 are equal,the value of k is