y=log(cosec x-cot x)

Evaluate the follow integrals: int (cosec x dx)/(log (cosec x- cot x))

If y=log (cosec x -cotx) ,then (dy)/(dx)

itn "cosec" x log ("cosec" x-cot x)dx=

If y=(cosec x-cot x)/(cosec x+cot x) then (dy)/(dx) is

Evaluate: int csc x log(csc x-cot x)dx

The derivative of log |cosec x -cot x | w.r.t x is

Evaluate int(log(csc x-cot x))/(sin x)dx

Consider the following statements I. If y=ln(secx+tanx) . then (dy)/(dx)=secx II. If y=ln("cosec"x-cotx) . then (dy)/(dx)="cosec"x Which of the above statements is/are correct ?

csc x=1+cot x