If 111 mg of `CaCl_(2)` and 12 mg of `MgSO_(4)` are present in 2L of water, what is its hardness (in gram `CaCO_(3)//p p m)` ?

If 11.1 mg of CaCl_2 and 12mg of MgSO_4 are present in 2 litres of water, what is its hardness (in grams of CaCO_3 /ppm)?

One litre of a sample of hard water contains 1 mg of CaCl_(2) and 1 mg of MgCl_(2) . Find the total hardness of water in terms of parts of CaCO_(3) per 10^(6) parts of water by mass.

One litre of sample of hard water contains 0.8 mg of CaCl_(2) and "0.8 mg of MgCl"_(2) . Find the total hardness in terms of parts of CaCO_(3) , per 10^(6) parts of water by mass.

One litre of sample of hard water contains 0.8 mg of CaCl_(2) and "0.8 mg of MgCl"_(2) . Find the total hardness in terms of parts of CaCO_(3) , per 10^(6) parts of water by mass.

One litre sample of water contains 0.9 mg CaCl_(2) and 0.9 mg of MgCl_(2) . Find the total hardness in terms of parts permillion of CaCO_(3) .

A water is said to be soft water if it produces sufficient foam with the soap and water that does not produce foam with soap is known as hard water. Hardness has been classified into two types (i)Temporary hardness (ii) Permanent hardness. Temporary hardness is due to presence of calcium and magnesium bicarbonate. It is simply removed by boiling as Ca(HCO_(3))_(2)overset(Delta)rarr CaCO_(3)darr+CO_(2)uarr+H_(2)O Mg(HCO_(3))_(2)overset(Delta)rarr MgCO_(3)darr+CO_(2)uarr+H_(2)O temporary hardness can also be removed by addition of slaked lime, Ca(OH)_(2) Ca(HCO_(3))_(2)+Ca(OH)_(2) to 2CaCO_(3)darr+2H_(2)O permanent hardsness is due to presencce of sulphates and chlorides of Ca,Mg,etc. It is removed by washing soda as CaCl_(2)+Na_(2)CO_(3) to CaCO_(3)darr+2NaCl CaSO(4)+Na_(2)CO_(3)to CaCO_(3)darr+Na_(2)SO_(4) Permanent hardness also removed by ion exchange resin process as 2RH+Ca^(2+)toR_(2)Ca+2H^(+) 2ROH+SO_(4)^(2-) to R_(2)SO_(4)+2OH^(-) The degree of hardness of water is measured in terms of PPm of CaCO_(3) 100 PPm means 100 g of CaCO_(3) is present in 10^(6) g of H_(2)O . If any other water sample which contain 120 PPm of MgSO_(4) , hardness in terms of CaCO_(3) is equal to =100 PPm. One litre of a sample of hard water (d=1 g/mL) cotains 136 mg of CaSO_(4) and 190 mg of MgCl_(2) . What is the total hardness of water in terms of CaCO_(3) ?

A water is said to be soft water if it produces sufficient foam with the soap and water that does not produce foam with soap is known as hard water. Hardness has been classified into two types (i)Temporary hardness (ii) Permanent hardness. Temporary hardness is due to presence of calcium and magnesium bicarbonate. It is simply removed by boiling as Ca(HCO_(3))_(2)overset(Delta)rarr CaCO_(3)darr+CO_(2)uarr+H_(2)O Mg(HCO_(3))_(2)overset(Delta)rarr MgCO_(3)darr+CO_(2)uarr+H_(2)O temporary hardness can also be removed by addition of slaked lime, Ca(OH)_(2) Ca(HCO_(3))_(2)+Ca(OH)_(2) to 2CaCO_(3)darr+2H_(2)O permanent hardsness is due to presencce of sulphates and chlorides of Ca,Mg,etc. It is removed by washing soda as CaCl_(2)+Na_(2)CO_(3) to CaCO_(3)darr+2NaCl CaSO(4)+Na_(2)CO_(3)to CaCO_(3)darr+Na_(2)SO_(4) Permanent hardness also removed by ion exchange resin process as 2RH+Ca^(2+)toR_(2)Ca+2H^(+) 2ROH+SO_(4)^(2-) to R_(2)SO_(4)+2OH^(-) The degree of hardness of water is measured in terms of PPm of CaCO_(3) 100 PPm means 100 g of CaCO_(3) is present in 10^(6) g of H_(2)O . If any other water sample which contain 120 PPm of MgSO_(4) , hardness in terms of CaCO_(3) is equal to =100 PPm. One litre of a sample of hard water (d=1 g/mL) cotains 136 mg of CaSO_(4) and 190 mg of MgCl_(2) . What is the total hardness of water in terms of CaCO_(3) ?

A 50 mL sample of hard water containing Ca^(2+) and Mg^(2+) ions is titrated with 50 mL. 0.005 M EDTA solution at pH=10 , using eriochrome balck -T indicator to reach equivalence point. In a equal amount of hard water sample, Mg^(2+) ions are precipitated as Mg(OH)_(2) by adding suitable amount of NaOH . the solution, after precipitation of Mg(OH)_(2) , is stirred and then titrated with EDTA solution using calcon as indicator, and it requires 10 mL of above EDTA solution to reach equivalence point. a. Calculate the strength of Ca^(2+) and Mg^(2+) ions present in hard water. b. Calculate the hardness due to Ca^(2+) ions in p p m of CaCO_(3) . c. Calculate the hardness due to Mg^(2+) ions in p p m of CaCO_(3) . d. Calculate the total hardness of water in p p m of CaCO_(3) .