[" The distance "x" moved by a body of mass "0.5kg" under the "],[" action of a force which varies with time "t" as "x(m)=3t^(2)+],[4t+5," where "t" is in second.The work done by the force in "],[" first "2" second is "]

The distance x moved by a body of mass 0.5 kg under the action of a force varies with time t as x(m)=3t^(2)+4t+5 Here, t is expressed in second. What is the work done by the force in first 2 seconds?

The distance x moved by a body of mass 0.5 kg under the action of a force varies with time t as x(m)=3t^(2)+4t+5 Here, t is expressed in second. What is the work done by the force in first 2 seconds?

A body of mass 5 kg at rest under the action of a force which gives its velocity given by v = 3 xx t m//s , here 't' is time in seconds. The work done by the force in two seconds will be

The distance x covered by a body of 2 kg under the action of a force is related to time t as x=t^(2)//4 . What is the work done by this force in 2 seconds ?

A body of mass 3 kg is under a constant force which causes a displacement s metre in it, given by the relation s=(1)/(3)t^(2) , where t is in seconds. Work done by the force in 2 seconds is

A body of mass 3 kg is under a constant force which causes a displacement s metre in it, given by the relation s=(1)/(3)t^(2) , where t is in seconds. Work done by the force in 2 seconds is

The relation between the displaement x and the time t for a body of mass 2 kg moving under the action of a force is given by x=t^3//3 , where x is in metre and t in second . Calculate the work done by the body in the first 2 seconds .