(1)/(2)+(1)/(6)+(1)/(9)" ant wadd "

1(1)/(3)+2(1)/(6)-3(1)/(9)=1div?

2(4)/(9)+3(1)/(6)

A special die is so constructed that the probabilities of throwing 1, 2, 3, 4, 5 and 6 are (1-k)/(6), (1+2k)/(6), (1-k)/(6), (1+k)/(6), (1-2k)/(6) and (1+k)/(6) , respectively. If two such dice are thrown and the probability of getting a sum equal to 9 lies between (1)/(9) and (2)/(9) , then the integral value of k is

Solve 7(1)/(2)-[2(1)/(4)+{1(1)/(4)-(1)/(2)(1(1)/(2)-(1)/(3)-(1)/(6))}]=?(2)/(9) (b) 4(1)/(2) (c) 9(1)/(2) (d) 1(77)/(228)

Find 5(1)/(6)-:(9)/(2)

Find the mean and standard deviation of each of the following probability distrribution: x_(i):012345p_(i):(1)/(6)(5)/(18)(2)/(9)(1)/(6)(1)/(9)(1)/(9)(1)/(18)

tan [(pi) / (4) + (1) / (2) (cos ^ (- 1)) (9) / (6)] + tan [(pi) / (4) - (1) / (2 ) (cos ^ (- 1)) (9) / (6)] =