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a^(2)+4b^(2)-4ab-4c^(2)...

a^(2)+4b^(2)-4ab-4c^(2)

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The sides of a triangleABC satisfy the equation 2a^(2) + 4b^(2) + c^(2) =4ab + 2ac , then-

The sides of DeltaABC satisfy the equation 2a^(2) + 4b^(2) + c^(2) = 4ab + 2ac . Then

Simplify: a^(2)b(a-b^(2))+ab^(2)(4ab-2a^(2))-a^(3)b(1-2b)

Factorize: a^2+4b^2-4a b-4c^2

Find the product : (i) (a+2b+4c)(a^(2)+4b^(2)+16c^(2)-2ab-8bc-4ca) (ii) (3x-5y-4)(9x^(2)+25y^(2)+15xy+12x-20y+16) (iii) (2-3b-7c)(4+9b^(2)+49c^(2)+6b-21bc+14c) (iv) (sqrt(2)a+2sqrt(2)b+c)(2a^(2)+8b^(2)+c^(2)-4ab-2sqrt(2)bc-sqrt(2)ac)

Find the product : (i) (a+2b+4c)(a^(2)+4b^(2)+16c^(2)-2ab-8bc-4ca) (ii) (3x-5y-4)(9x^(2)+25y^(2)+15xy+12x-20y+16) (iii) (2-3b-7c)(4+9b^(2)+49c^(2)+6b-21bc+14c) (iv) (sqrt(2)a+2sqrt(2)b+c)(2a^(2)+8b^(2)+c^(2)-4ab-2sqrt(2)bc-sqrt(2)ac)

The factors of 8a^(3)+b^(3)-6ab+1 are (a) (2a+b-1)(4a^(2)+b^(2)+1-3ab-2a) (b) (2a-b+1)(4a^(2)+b^(2)-4ab+1-2a+b)(2a+b+1)(4a^(2)+b^(2)+1-2ab-b-2a) (d) (2a-1+b)(4a^(2)+1-4a-b-2ab)

Factorise : 4a^(2)-4ab-c^(2)-2bc