In Newton's second `vecF=mveca` (for constant mass m), `veca` is the acceleration of the mass m with respect to

In the above question, the acceleration of mass m is

Explain the physical significance of the equation MvecA=vecF_(ext) , where 'M' is the mass of the whole rotating body and vecA is the acceleration of the centre of mass of the system of particles.

In the arrangement shown in the fig. the block of mass m lies on the wedge. Wedge is moving with acceleration a = 5 m/sec Find the wedge acceleration of the block with respect to wedge.

Two masses, m and 2m are connected by a string that passes over a frictionless pulley. When the mass 2m is released, acceleration of the mass m upwards, will be

In the arrangement shown in the fig. the block of mass m lies on the wedge. Wedge is moving with acceleration a = 5 m/sec . Find the wedge acceleration of the block with respect to wedge.

Two point masses, each of mass 'm' are connected to the end of spring. If force F is applied on one of the mass, then find the acceleration of this mass if the acceleration of other mass is a ?

A person rides a bike with a constant velocity vecv with respect to ground and another biker accelerates with acceleration ā with respect to ground. Who can apply Newton's second law with respect to a stationary observer on the ground?

A body of mass M is moving in +x-direction with acceleration a. Find the minimum value of mu so that a body of mass m can be held stationary with respect to M, on the vertical side of M.