" 17.यडि "sin theta=(p)/(sqrt(p^(2)+q^(2)))," Then prove that : "

If sin theta= (p)/(sqrt(p^(2)+q^(2))) then prove that qsin theta=p cos theta

ABCD is a trapezium such that AB and CD are parallel and BC bot CD . If angleADB = theta, BC = p and CD = q , then AB is equal to (a) ((p^(2)+q^(2))sin theta)/(p cos theta +q sin theta) (b) (p ^(2) + q ^(2)cos theta)/(p cos theta +q sin theta) (c) (p ^(2)+ q^(2))/(p^(2)cos theta +q^(2) sin theta) (d) ((p^(2) +q^(2))sin theta)/((p cos theta + sin theta)^(2))

if : p*cos theta=sqrt(p^(2)+q^(2)).sin theta, "then" : q * sin theta=

If qcosectheta=p and theta is acute then value of (sqrt(p^(2)-q^(2)))tan theta is

If costheta + sin theta = sqrt2 cos theta , prove that cos theta - sin theta = sqrt2 sin theta .

If p^(2) = a^(2) cos^(2) theta + b^(2) sin^(2)theta , prove that p + (d^(2p)/(d theta^(2))) =(a^(2)b^(2))/p^(3)

If cos theta + sin theta = p and sec theta + cosec theta = q , prove that q (p^(2) - 1) = 2p .

ABCD is a trapezium such that AB|CD and CB is perpendicular to them.If /_ADB=theta,BC=p, and CD=q, show that AB=((p^(2)+q^(2))sin theta)/(p cos theta+q sin theta)