Specific reaction rate of a gaseous reaction is `6.8 xx 10^(-8)"atmoshere"^(-1)"second"^(-1)`. Calculate its specific reaction rate in litre `"mole^(-1)"second"^(-1)` unit.

Explanation

To convert the specific reaction rate from the unit of \( \text{atmosphere}^{-1} \text{second}^{-1} \) to \( \text{litre} \, \text{mole}^{-1} \text{second}^{-1} \), we can follow these steps:

### Step 1: Understand the Given Rate
The specific reaction rate is given as:
\[ k = 6.8 \times 10^{-8} \, \text{atmosphere}^{-1} \text{second}^{-1} \]

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