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The rate constant for the reaction 2N...

The rate constant for the reaction
`2N_(2)O_(5)to4NO_(2)+O_(2), "is"" " 3.0xx10^(-5)S^(-1)`. If the rate is
`2.40xx10^(-5)"mol"L^(-1)s^(-1)` then the concentration of
`N_(2)O_(5)("in mol" L^(-1))` is

A

1.4

B

1.2

C

0.04

D

0.05

Text Solution

Verified by Experts

The correct Answer is:
D
`2N_2O_5(g) to 4NO_2(g) + O_2(g)`
Rate of reaction ` = -(d[N_2O_5])/(dt) = k[N_2O_5]`
`:. 2.40 xx 10^(-5) = 3.0 xx 10^(-5) xx [N_2O_5]`
`:. [N_2O_5]= (2.40 xx 10^(-5))/(3.0 xx 10^(-5))=0.8 mol//L`
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