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If doubling the concentration of a react...

If doubling the concentration of a reactant ‘A’ increases the rate 8 times and tripling the concentration of ‘A’ increases the rate 27 times, the rate is proportional to:

A

Concentration of ‘A’

B

Square of concentration of ‘A’

C

Under root of the concentration of ‘A’

D

Cube of concentration of ‘A’

Text Solution

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The correct Answer is:
To solve the problem step-by-step, we need to analyze the relationship between the concentration of reactant A and the rate of the reaction based on the information provided. ### Step 1: Understand the relationship between concentration and rate The rate of a reaction can be expressed as: \[ \text{Rate} = k [A]^n \] where: - \( k \) is the rate constant, - \( [A] \) is the concentration of reactant A, - \( n \) is the order of the reaction with respect to A. ### Step 2: Set up the equations based on the given information 1. When the concentration of A is doubled (\( [A] \to 2[A] \)), the rate increases 8 times: \[ R_1 = k (2[A])^n = 8R \] This implies: \[ 8R = k (2[A])^n \] 2. When the concentration of A is tripled (\( [A] \to 3[A] \)), the rate increases 27 times: \[ R_2 = k (3[A])^n = 27R \] This implies: \[ 27R = k (3[A])^n \] ### Step 3: Divide the two equations To eliminate \( k \) and \( R \), we can divide the first equation by the second: \[ \frac{8R}{27R} = \frac{k (2[A])^n}{k (3[A])^n} \] This simplifies to: \[ \frac{8}{27} = \frac{(2[A])^n}{(3[A])^n} \] Since \( [A] \) cancels out, we have: \[ \frac{8}{27} = \left(\frac{2}{3}\right)^n \] ### Step 4: Solve for \( n \) We can express \( 8 \) and \( 27 \) as powers: \[ 8 = 2^3 \quad \text{and} \quad 27 = 3^3 \] Thus: \[ \frac{2^3}{3^3} = \left(\frac{2}{3}\right)^n \] This leads to: \[ \left(\frac{2}{3}\right)^3 = \left(\frac{2}{3}\right)^n \] From this, we can conclude that: \[ n = 3 \] ### Step 5: Determine the proportionality of the rate Since we found that \( n = 3 \), we can express the rate as: \[ \text{Rate} = k [A]^3 \] This means that the rate is proportional to the cube of the concentration of A. ### Conclusion The rate is proportional to \( [A]^3 \).
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