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For the following reaction scheme (homog...

For the following reaction scheme (homogeneous), the rate constant has units : `A + B oversetKto C`

A

`sec^(-1)"mole"`

B

`sec^(-1)`

C

`sec^(-1).L per mole

D

sec

Text Solution

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The correct Answer is:
To determine the units of the rate constant \( k \) for the reaction \( A + B \overset{k}{\rightarrow} C \), we will follow these steps: ### Step 1: Write the Rate Law The rate law for the reaction can be expressed as: \[ \text{Rate} = k [A]^m [B]^n \] For the reaction \( A + B \rightarrow C \), we assume it is a simple elementary reaction, which means the order of the reaction is the sum of the stoichiometric coefficients. Here, both \( A \) and \( B \) have a coefficient of 1, so: - \( m = 1 \) (for \( A \)) - \( n = 1 \) (for \( B \)) Thus, the rate law can be written as: \[ \text{Rate} = k [A]^1 [B]^1 = k [A][B] \] ### Step 2: Express the Rate in Terms of Concentration The rate of a reaction is defined as the change in concentration of a reactant or product per unit time. Therefore, we can express the rate as: \[ \text{Rate} = \frac{\Delta [C]}{\Delta t} \] In terms of concentration, the unit of rate is: \[ \text{Rate} = \text{mol/L/s} \quad \text{(moles per liter per second)} \] ### Step 3: Substitute the Rate into the Rate Law Now, substituting the expression for the rate into the rate law: \[ \frac{\Delta [C]}{\Delta t} = k [A][B] \] ### Step 4: Rearrange to Solve for \( k \) Rearranging the equation to solve for \( k \): \[ k = \frac{\text{Rate}}{[A][B]} \] ### Step 5: Substitute Units into the Equation Substituting the units into the equation: - The unit of rate is \( \text{mol/L/s} \) - The unit of concentration \( [A] \) and \( [B] \) is \( \text{mol/L} \) Thus, the units for \( k \) become: \[ k = \frac{\text{mol/L/s}}{(\text{mol/L})(\text{mol/L})} \] This simplifies to: \[ k = \frac{\text{mol/L/s}}{\text{mol}^2/\text{L}^2} = \frac{\text{mol/L/s}}{\text{mol}^2/\text{L}^2} = \frac{\text{L}^2}{\text{mol}^2 \cdot \text{s}} \cdot \text{mol} = \frac{1}{\text{mol} \cdot \text{s}} \cdot \text{L} = \text{L/s/mol} \] ### Final Answer The units of the rate constant \( k \) for the reaction \( A + B \rightarrow C \) are: \[ \text{L} \cdot \text{s}^{-1} \cdot \text{mol}^{-1} \]
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