The order of a reaction which has the rate expression `(dc)/(dt) = k[E]^(3//2)[D]^(3//2)` is

Options

A. `3//2`
B. 3
C. 2
D. 0

Answer

To determine the order of the reaction from the given rate expression, we will follow these steps:

### Step 1: Identify the Rate Expression
The rate expression provided is:
\[ \frac{dc}{dt} = k[E]^{\frac{3}{2}}[D]^{\frac{3}{2}} \]

### Step 2: Understand the Concept of Reaction Order
The order of a reaction is defined as the sum of the powers of the concentration terms in the rate law expression. In this case, we have two reactants, E and D, with their respective powers.

### Step 3: Identify the Exponents
From the rate expression:
- The exponent for [E] is \(\frac{3}{2}\)
- The exponent for [D] is \(\frac{3}{2}\)

### Step 4: Sum the Exponents
To find the overall order of the reaction, we sum the exponents:
\[ \text{Order} = \frac{3}{2} + \frac{3}{2} \]

### Step 5: Perform the Calculation
Calculating the sum:
\[ \text{Order} = \frac{3}{2} + \frac{3}{2} = \frac{3 + 3}{2} = \frac{6}{2} = 3 \]

### Conclusion
The order of the reaction is **3**.

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