The reaction `2A to 4B+C` follows first order kinetics. Hence, the molecularity of the reaction is:

Options

A. Unimolecular
B. Pseudo–unimolecular
C. Bimolecular
D. None of the above

Answer

To determine the molecularity of the reaction \(2A \rightarrow 4B + C\) that follows first-order kinetics, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Definition of Molecularity**:
- Molecularity refers to the number of reactant molecules that participate in an elementary reaction. It is defined only for elementary reactions, which occur in a single step.

2. **Identify the Reaction**:
- The given reaction is \(2A \rightarrow 4B + C\). Here, we have two molecules of \(A\) reacting.

3. **Determine the Type of Reaction**:
- Since the reaction involves two molecules of the same reactant \(A\) (i.e., \(2A\)), it can be classified as bimolecular.

4. **Conclusion**:
- The molecularity of the reaction \(2A \rightarrow 4B + C\) is bimolecular because it involves two molecules of \(A\) in the elementary step.

### Final Answer:
The molecularity of the reaction is **bimolecular**.

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