In the reaction `Li_3^6 + (?) to He_2^4 + H_1^3`. The missing particle is:

Options

A. Electron
B. Neutron
C. Proton
D. Deutron

Answer

To find the missing particle in the nuclear reaction \( Li_3^6 + (?) \rightarrow He_2^4 + H_1^3 \), we will follow these steps:

### Step 1: Identify the known quantities
The reaction involves:
- Lithium-6 (\( Li_3^6 \))
- Helium-4 (\( He_2^4 \))
- Tritium (\( H_1^3 \))

### Step 2: Write down the mass numbers and atomic numbers
- For \( Li_3^6 \):
- Mass number (A) = 6
- Atomic number (Z) = 3

- For \( He_2^4 \):
- Mass number (A) = 4
- Atomic number (Z) = 2

- For \( H_1^3 \):
- Mass number (A) = 3
- Atomic number (Z) = 1

### Step 3: Set up the equations for mass number and atomic number
Let the missing particle be represented as \( X \) with mass number \( A_X \) and atomic number \( Z_X \).

From the mass numbers:
\[ 6 + A_X = 4 + 3 \]
\[ 6 + A_X = 7 \implies A_X = 7 - 6 = 1 \]

From the atomic numbers:
\[ 3 + Z_X = 2 + 1 \]
\[ 3 + Z_X = 3 \implies Z_X = 3 - 3 = 0 \]

### Step 4: Identify the missing particle
The missing particle has:
- Mass number \( A_X = 1 \)
- Atomic number \( Z_X = 0 \)

This corresponds to a neutron, which is denoted as \( n \) or \( ^1_0n \).

### Conclusion
The missing particle in the reaction \( Li_3^6 + (?) \rightarrow He_2^4 + H_1^3 \) is a neutron.

### Final Answer
The missing particle is a neutron (\( n \)).

---