Deuterons when bombarded on a nuclide produce`Ar_18^38` and neutrons. The target is:

Options

A. `Cl_17^35`
B. `K_19^27`
C. `Cl_17^37`
D. `K_19^39`

Answer

To find the target nuclide that deuterons bombard to produce Argon-38 and neutrons, we can follow these steps:

### Step 1: Identify the Reaction
The reaction can be represented as:
\[ \text{Deuteron} + \text{Target Nuclide} \rightarrow \text{Argon-38} + \text{Neutrons} \]

### Step 2: Write Down the Known Values
From the question, we know:
- Argon-38 has an atomic number (Z) of 18 and a mass number (A) of 38.
- The deuteron (which is a hydrogen isotope) has 1 proton and 1 neutron, represented as \( ^2_1H \).

### Step 3: Set Up the Equation
Let the target nuclide be represented as \( X \) with atomic number \( Z_X \) and mass number \( A_X \). The reaction can be balanced as follows:
\[ ^2_1H + X \rightarrow ^{38}_{18}Ar + n \]

### Step 4: Balance the Atomic Numbers
Balancing the atomic numbers (Z):
\[ 1 + Z_X = 18 + 0 \]
This simplifies to:
\[ Z_X = 18 - 1 = 17 \]

### Step 5: Balance the Mass Numbers
Balancing the mass numbers (A):
\[ 2 + A_X = 38 + 1 \]
This simplifies to:
\[ A_X = 38 + 1 - 2 = 37 \]

### Step 6: Identify the Target Nuclide
Now we have determined that the target nuclide \( X \) has:
- Atomic number \( Z_X = 17 \)
- Mass number \( A_X = 37 \)

Looking at the periodic table, the element with atomic number 17 is Chlorine (Cl).

### Conclusion
Therefore, the target nuclide is:
\[ \text{Chlorine-37} \, (^{37}_{17}Cl) \]