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The reaction which disintegrates neutron...

The reaction which disintegrates neutron is or neutron is emitted (which completes first):

A

`Am_96^240 + He_2^4 to Bk_97^244 + e_(+1)^0`

B

`P_15^30 to Si_14^30 + e_(+1)^0`

C

`H_1^1 + C_6^12 to N_7^13`

D

`Al_13^27 + He_2^4 to P_15^30`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding which reaction emits a neutron, we need to analyze the given nuclear reactions step by step. ### Step 1: Understand the properties of a neutron A neutron is a subatomic particle with the following properties: - Charge: Neutral (0) - Atomic Number: 0 - Mass Number: 1 ### Step 2: Analyze the given reactions We need to check each reaction to see if it emits a neutron while ensuring that both atomic and mass numbers are balanced. #### Reaction 1: \[ \text{Am}^{240}_{96} + \text{He}^{4}_{2} \rightarrow \text{Bk}^{244}_{97} + \text{e}^{+}_{1} + \text{0}^{1} \] - **Atomic Number Check**: - Left Side: \( 96 + 2 = 98 \) - Right Side: \( 97 + 1 = 98 \) (Balanced) - **Mass Number Check**: - Left Side: \( 240 + 4 = 244 \) - Right Side: \( 244 + 0 = 244 \) (Balanced) This reaction does not emit a neutron. #### Reaction 2: \[ \text{X}^{30}_{15} \rightarrow \text{Y}^{30}_{14} + \text{e}^{+}_{1} \] - **Atomic Number Check**: - Left Side: \( 15 \) - Right Side: \( 14 + 1 = 15 \) (Balanced) - **Mass Number Check**: - Left Side: \( 30 \) - Right Side: \( 30 + 0 = 30 \) (Balanced) This reaction does not emit a neutron. #### Reaction 3: \[ \text{H}^{1}_{1} + \text{C}^{12}_{6} \rightarrow \text{?} \] - **Atomic Number Check**: - Left Side: \( 1 + 6 = 7 \) - Right Side: Should be \( 7 \) (not provided) - **Mass Number Check**: - Left Side: \( 1 + 12 = 13 \) - Right Side: Should be \( 13 \) (not provided) This reaction does not emit a neutron. #### Reaction 4: \[ \text{X}^{27}_{13} + \text{He}^{4}_{2} \rightarrow \text{Y}^{30}_{15} + \text{n}^{1}_{0} \] - **Atomic Number Check**: - Left Side: \( 13 + 2 = 15 \) - Right Side: \( 15 \) (Balanced) - **Mass Number Check**: - Left Side: \( 27 + 4 = 31 \) - Right Side: \( 30 + 1 = 31 \) (Balanced) This reaction emits a neutron. ### Step 3: Conclusion From the analysis, the fourth reaction is the only one that emits a neutron. Thus, the correct answer is: **The reaction that emits a neutron is the fourth reaction.** ---
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