Benzene diazoniumtetrafluoro borate `overset(Delta) to` Product (A) . In the above process product A is

Options

A. Fluorobenzene
B. Benzene
C. 1, 4- difluorobenzene
D. 1, 3- difluorobenzene

Answer

To solve the question regarding the product (A) formed from the heating of benzene diazonium tetrafluoroborate, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactant is benzene diazonium tetrafluoroborate. Its structure can be represented as:
- Benzene (C6H6) is a cyclic hydrocarbon with alternating double bonds.
- The diazonium part is represented as -N2^+ (a nitrogen-nitrogen triple bond with a positive charge).
- The tetrafluoroborate part is BF4^− (a boron atom bonded to four fluorine atoms).

2. **Write the Structure**: The complete structure can be illustrated as:
- C6H5-N2^+BF4^−
- This indicates that the diazonium group is attached to a benzene ring, and the tetrafluoroborate acts as a counterion.

3. **Heating the Compound**: Upon heating, the diazonium group (N2^+) is released as nitrogen gas (N2). This is a key step as the release of nitrogen gas drives the reaction forward.

4. **Formation of Carbocation**: The loss of the diazonium group results in the formation of a carbocation (C6H5^+). This carbocation is highly reactive and can undergo further reactions.

5. **Nucleophilic Attack by Fluoride Ion**: The tetrafluoroborate ion (BF4^−) can release a fluoride ion (F^−). This fluoride ion can then attack the carbocation formed in the previous step.

6. **Formation of Product (A)**: The final product formed from the nucleophilic attack is fluorobenzene (C6H5F). The reaction can be summarized as:
- C6H5-N2^+BF4^− → C6H5F + N2 + BF3

7. **Conclusion**: Therefore, the product (A) formed from the heating of benzene diazonium tetrafluoroborate is fluorobenzene.

### Final Answer:
The product (A) is **fluorobenzene (C6H5F)**.