Silver Acetate + `Br_(2) overset(CS_(2)) to` Main Product . The major product of this reaction is

Options

A. `CH_(3)Br`
B. `CH_(3)COI`
C. `CH_(3)COOH`
D. None of these

Answer

To determine the major product of the reaction between silver acetate and bromine in the presence of carbon disulfide (CS2), we can follow these steps:

### Step 1: Understand the Reactants
- **Silver Acetate (AgOAc)**: The structure of silver acetate can be represented as CH3COOAg. It consists of an acetate group (CH3COO-) and a silver ion (Ag+).
- **Bromine (Br2)**: A diatomic molecule that can act as an electrophile in reactions.

### Step 2: Reaction Setup
- When silver acetate reacts with bromine in CS2, the solvent (CS2) helps facilitate the reaction. The acetate ion (OAc-) will interact with bromine.

### Step 3: Formation of the Adduct
- The acetate ion (OAc-) will attack one of the bromine atoms in Br2, resulting in the formation of an adduct. This can be represented as:
\[ CH3COO^- + Br_2 \rightarrow CH3COOBr + Ag^+ \]
- The product formed here is bromoacetate (CH3COOBr) and silver ion.

### Step 4: Heating the Reaction
- Upon heating, a homolytic bond fission occurs. This means that the bonds break to form free radicals. The O-O bond in the acetate can break, leading to the formation of a carbon radical and a bromine radical.

### Step 5: Free Radical Mechanism
- The free radical formed from the acetate will rearrange, and the bromine radical will react with the carbon radical. The carbon radical will take the bromine, leading to the formation of bromomethane (CH3Br).

### Step 6: Final Product
- The final major product of this reaction is **Bromomethane (CH3Br)**.

### Conclusion
Thus, the major product of the reaction between silver acetate and bromine in the presence of CS2 is **Bromomethane (CH3Br)**.

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