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For the cell, Zn(s)abs(Zn^(2+))abs(Cu^(2...

For the cell, `Zn(s)abs(Zn^(2+))abs(Cu^(2+))Cu(s)`, the standard cell voltage, `E^(0)""_(cell)` is `1.10` V. When a cell using these reagents was prepared in the lab, the measured cell voltage was `0.98 ` One possible explanation for the observed voltage is :

A

there were `2.00` mole of `Cu^(2+)` but only `1.00` mol of `Zn^(2+)`

B

the Zn electrode had twice the surface area as that of the Cu electrode

C

the `[Zn^(2+)]` concentration was larger than the `[Cu^(2+)]` concentration

D

the volume of the `Zn^(2+)` ion solution was greater than the volume of the `Cu^(2+)` ion solution.

Text Solution

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The correct Answer is:
C
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