A conducting wire carries a current of `0.965` ampere. Rate of flow of electrons per second at a given point is :

Options

A. `1xx10^(-5)N_(A)`
B. `N_(A)`
C. `0.965N_(A)`
D. `(N_(A))/(0.965)`

Answer

To find the rate of flow of electrons per second in a conducting wire carrying a current of 0.965 amperes, we can follow these steps:

### Step 1: Understand the Relationship Between Current and Charge
The current (I) in a wire is defined as the amount of charge (Q) that passes through a point in the wire per unit time (t). The formula for current is given by:
\[ I = \frac{Q}{t} \]
Where:
- \( I \) is the current in amperes (A),
- \( Q \) is the charge in coulombs (C),
- \( t \) is the time in seconds (s).

### Step 2: Calculate the Charge Flowing in One Second
Since the current is given as 0.965 A and we are considering a time period of 1 second, we can rearrange the formula to find the charge:
\[ Q = I \times t \]
Substituting the values:
\[ Q = 0.965 \, \text{A} \times 1 \, \text{s} = 0.965 \, \text{C} \]

### Step 3: Determine the Charge of a Single Electron
The charge of a single electron (e) is approximately:
\[ e = 1.6 \times 10^{-19} \, \text{C} \]

### Step 4: Calculate the Number of Electrons Flowing Per Second
To find the number of electrons (n) flowing per second, we can use the formula:
\[ n = \frac{Q}{e} \]
Substituting the values we have:
\[ n = \frac{0.965 \, \text{C}}{1.6 \times 10^{-19} \, \text{C}} \]

### Step 5: Perform the Calculation
Calculating the above expression:
\[ n = \frac{0.965}{1.6 \times 10^{-19}} \]
\[ n \approx 6.03125 \times 10^{18} \]

### Step 6: Round the Result
We can round this to:
\[ n \approx 6.03 \times 10^{18} \]

### Conclusion
The rate of flow of electrons per second at a given point in the wire is approximately:
\[ 6.03 \times 10^{18} \, \text{electrons/second} \]

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