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Consider the cell reaction Zn+Cu^(2+)(aq...

Consider the cell reaction `Zn+Cu^(2+)(aq)iff Cu + Zn^(2+)` (aq). Reaction quotient is `Q = ([Zn^(2+)])/([Cu^(2+)])E^(0)` of the cell is `1.10V.` Now, `E_(cell)` will be `1.159V` when:

A

`([Cu^(2+)])/([Zn^(2+)]) = 0.01`

B

`([Zn^(2+)])/([Cu^(2+)]) = 0.01`

C

`([Zn^(2+)])/([Cu^(2+)]) = 0.1`

D

`([Zn^(2+)])/([Cu^(2+)]) = 1`

Text Solution

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The correct Answer is:
B
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