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Cu^(2+) + 2e rarr Cu(s). For the graph b...

`Cu^(2+) + 2e rarr Cu(s)`. For the graph between `log[Cu^(2+)]` versus `E_("red")` a straight line of intercept `0.34` V is obtained. Then electrode potential of the half-cell `Cu// Cu^(2+)(0.1 M)` will be :

A

`[0.34+(0.0591)/2]V`

B

`[-0.34-(0.0591)/2]V`

C

`0.34 V`

D

`[-0.34+(0.0591)/2]V`

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The correct Answer is:
D
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