Home
Class 12
CHEMISTRY
The resistance of 0.01 N solution of an ...

The resistance of `0.01` N solution of an electrolyte waw found to be 210 ohm at 298 K, when a conductivity cell with cell constant `0.66 cm^(-1)` is used. The equivalent conductance of solution is:

A

`314.28` mho `cm^(2)eq^(-1)`

B

`3.14` mho `cm^(2)eq^(-1)`

C

`31.428` mho `cm^(2)eq^(-1)`

D

`0.314` mho `cm^(2)eq^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

The resistance of 0.01 N solution of an electrolyte was found to be 220 ohm at 298 K using a conductivity cell with a cell constant of 0. 88cm^(-1) . The value of equivalent conductance of solution is

The resistance of a 0.01N solution of an electroyte was found to 210 ohm at 298K using a conductivity cell with a cell constant of 0.88 cm^(-1) . Calculate specific conductance and equilvalent conductance of solution.

The resistance of 0.01N solution of an electrolyte AB at 328K is 100ohm. The specific conductance of solution is cell constant = 1cm^(-1)

The resistance of 0.01N solution of an electrolysis is 210 Omega at 298 K with a cell constant of 0.88 cm^(-1) . Calculate the conductivity and equivalent conducitivty of the solution.

The resistance of 0.1 N solution of a salt is found to be 2.5xx10^(3) Omega . The equivalent conductance of the solution is (Cell constant =1.15 cm^(-1) )

The equivalent conductance of a 0.2 n solution of an electrolyte was found to be 200Omega^(-1) cm^(2)eq^(-1) . The cell constant of the cell is 2 cm^(-1) . The resistance of the solution is