Home
Class 12
CHEMISTRY
Molar conductivities (wedge(m)^(infty)) ...

Molar conductivities `(wedge_(m)^(infty))` at infinite dilution of `NaCl, HCl and CH_(3)COONa` are `126.4, 425.9 and 91.0 S cm^(2) mol^(–1)` respectively. `wedge_(m)^(infty)` for `CH_(3)COOH` will be:

A

`290.8 S cm^(2) mol^(–1) `

B

`390.5 S cm^(2) mol^(–1) `

C

`425.5 S cm^(2) mol^(–1) `

D

`180.5 S cm^(2) mol^(–1) `

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Similar Questions

Explore conceptually related problems

Molar conductivities (Lambda_(m)^(@)) at infinite dilution of NaCl, HCl and CH_(3)COONa arc 126.4, 425.9 and 91.0 S cm^(2) mol^(-1) respectively. Lambda_(m)^(@) for CH_(3)COOH will be

Molar conductiveiy [Lambda _m] at infinite dilution of Na CL, HCl and CH_3 COONa are 126.4, 425, 9 and 91 0 S cm^2 "mol"^(-1) respectively, Lambda_m for CH_3COOH will be ,

If the molar conductivities at infinited dilution of NaCl, HCl and CH_(3)COONa are 126.4, 426.1 and 91.0 ohm^(-1) cm^(2) mol^(-1) respectively. What will be the that of acetic acid?

wedge_(m)^(@) for NaCl,HCl , and NaAc are 126.4, 425.9, and 91.0 S cm^(2) mol^(-1) , respectively . Calculate wedge ^(@) for Hac.

Calculate molar conducity of CH_(3)COOH at infinit e dilution if A_(m)^(@) for NACI,HCI and CH_(3)COONA are 126,45,426.16 an 91 S cm^(2) mol^(-1) respectively

If molar conductivities (Lambda_m^0) at infinite dilution of KBr, HBr and CH_3COOK are 151.6, 427.7 and 114.4 S cm^2 mol ^(-1) respectively then (Lambda_m^0) for CH_3COOH will be

overset(@)wedge for NaCI HCI and NaAC are 126.4 425.9 , and 91.0 S cm^(2) "mol"^(-1) respectively calulate overset(infty)wedge m for Hac.

The molar conductance of HCl, NaCl and CH_(3)COONa are 426,12 6 and 91 Omega^(-1)cm^(2)"mol"^(-1) respectively. The molar c onductance for CH_(3)COOH is