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Given that for a reaction of nth order, ...

Given that for a reaction of nth order, the integrated rate equation is:
`K=1/(t(n-1))[1/C^(n-1)-1/C_(0)^(n-1)]`, where `C` and `C_(0)` are the concentration of reactant at time `t` and initially respectively. The `t_(3//4)` and `t_(1//2)` are related as `t_(3//4)` is time required for C to become `C_(1//4`) :

A

`t_(3//4)=t_(1///2) [2^(n-1)+1]`

B

`t_(3//4)=t_(1///2) [2^(n-1)-1]`

C

`t_(3//4)=t_(1///2) [2^(n-1)-1]`

D

`t_(3//4)=t_(1///2) [2^(n+1)+1]`

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The correct Answer is:
A
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