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The rate of disapperance of Q in the rea...

The rate of disapperance of Q in the reaction `2P+Q to 2R+3S` is `2 times 10^-2` moles `l^-1 s^-1`. Which of the following statement is not true?

A

`-(d[P])/(dt)=4 times 10^-2 moles l^-1 s^-1`

B

`+(d[S])/(dt)=6times 10^-2 moles l^-1 s^-1`

C

`+1/2 (d[R])/(dt)=2 times 10^-2 moles l^-1 s^-1`

D

`+(d[R])/(dt)=2 times 10^-2 moles l^-1 s^-1`

Text Solution

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The correct Answer is:
To solve the problem, we need to analyze the given reaction and the rates of disappearance and formation of the reactants and products. The reaction is: \[ 2P + Q \rightarrow 2R + 3S \] We are given that the rate of disappearance of \( Q \) is \( 2 \times 10^{-2} \) moles \( l^{-1} s^{-1} \). ### Step 1: Write the rate expressions for the reaction From the stoichiometry of the reaction, we can express the rates of disappearance and formation as follows: - Rate of disappearance of \( P \): \[ -\frac{1}{2} \frac{d[P]}{dt} \] - Rate of disappearance of \( Q \): \[ -\frac{d[Q]}{dt} \] - Rate of formation of \( R \): \[ \frac{1}{2} \frac{d[R]}{dt} \] - Rate of formation of \( S \): \[ \frac{1}{3} \frac{d[S]}{dt} \] ### Step 2: Relate the rates using the given information We know that the rate of disappearance of \( Q \) is given as: \[ -\frac{d[Q]}{dt} = 2 \times 10^{-2} \, \text{moles} \, l^{-1} s^{-1} \] Thus, we can write: \[ \frac{d[Q]}{dt} = -2 \times 10^{-2} \, \text{moles} \, l^{-1} s^{-1} \] ### Step 3: Calculate the rate of disappearance of \( P \) Using the stoichiometric coefficients, we relate the rate of disappearance of \( P \) to that of \( Q \): \[ -\frac{1}{2} \frac{d[P]}{dt} = -\frac{d[Q]}{dt} \] Substituting the value of \( \frac{d[Q]}{dt} \): \[ -\frac{1}{2} \frac{d[P]}{dt} = 2 \times 10^{-2} \] Thus, we find: \[ \frac{d[P]}{dt} = -4 \times 10^{-2} \, \text{moles} \, l^{-1} s^{-1} \] ### Step 4: Calculate the rate of formation of \( R \) Using the stoichiometric coefficients again: \[ \frac{1}{2} \frac{d[R]}{dt} = -\frac{d[Q]}{dt} \] Substituting the value of \( \frac{d[Q]}{dt} \): \[ \frac{1}{2} \frac{d[R]}{dt} = 2 \times 10^{-2} \] Thus, we find: \[ \frac{d[R]}{dt} = 4 \times 10^{-2} \, \text{moles} \, l^{-1} s^{-1} \] ### Step 5: Calculate the rate of formation of \( S \) Using the stoichiometric coefficients: \[ \frac{1}{3} \frac{d[S]}{dt} = -\frac{d[Q]}{dt} \] Substituting the value of \( \frac{d[Q]}{dt} \): \[ \frac{1}{3} \frac{d[S]}{dt} = 2 \times 10^{-2} \] Thus, we find: \[ \frac{d[S]}{dt} = 6 \times 10^{-2} \, \text{moles} \, l^{-1} s^{-1} \] ### Step 6: Analyze the options Now we can analyze the options provided in the question: 1. Rate of disappearance of \( P \): \( 4 \times 10^{-2} \, \text{moles} \, l^{-1} s^{-1} \) (True) 2. Rate of formation of \( S \): \( 6 \times 10^{-2} \, \text{moles} \, l^{-1} s^{-1} \) (True) 3. Rate of formation of \( R \): \( 4 \times 10^{-2} \, \text{moles} \, l^{-1} s^{-1} \) (False, it should be \( 2 \times 10^{-2} \)) 4. Rate of formation of \( R \): \( 2 \times 10^{-2} \, \text{moles} \, l^{-1} s^{-1} \) (True) ### Conclusion The statement that is **not true** is the one regarding the rate of formation of \( R \) being \( 2 \times 10^{-2} \, \text{moles} \, l^{-1} s^{-1} \).
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