Inversion of cane sugar is a:

Options

A. First order reactions
B. Zero order reactions
C. second order reaction
D. Third order reactions

Answer

To determine the order of the reaction for the inversion of cane sugar, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reaction**: The inversion of cane sugar (sucrose) can be represented by the following chemical equation:
\[ \text{C}_{12}\text{H}_{22}\text{O}_{11} + \text{H}_2\text{O} \xrightarrow{\text{H}^+} \text{C}_6\text{H}_{12}\text{O}_6 + \text{C}_6\text{H}_{12}\text{O}_6 \]
Here, sucrose reacts with water in the presence of an acid (H⁺ ion) to produce glucose and fructose.

2. **Determine the Reactants**: In this reaction, we have two reactants: sucrose and water.

3. **Analyze Concentration**: In typical conditions, water is present in excess compared to sucrose. This means that the concentration of water remains relatively constant throughout the reaction.

4. **Rate-Determining Step**: The rate of the reaction is primarily determined by the concentration of sucrose because it is the limiting reactant. The excess water does not significantly affect the rate.

5. **Classify the Reaction Order**: Since the rate of the reaction depends on the concentration of only one reactant (sucrose), we can classify this reaction as a first-order reaction with respect to sucrose.

6. **Pseudo First-Order Reaction**: Although the reaction involves two reactants, the presence of excess water allows us to treat it as a pseudo first-order reaction. This is because we can consider the concentration of water to be constant, simplifying the reaction to first-order kinetics with respect to sucrose.

7. **Conclusion**: Therefore, the inversion of cane sugar is classified as a pseudo first-order reaction. However, since the question does not specify "pseudo," we can simply state that it is a first-order reaction.

### Final Answer:
The inversion of cane sugar is a first-order reaction.

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