[" If "f(x)=x^(a)log x" and "f(0)=0," If Rolle's theorem can be applied to "f" in "[0,1]," the "],[" value of "alpha" can be "]

If f(x) = x^(a) log x and f(0) = 0 then the value of alpha for which Rolle's theorem can be applied in [0,1] is

If f(x) = x^(a) log x and f(0) = 0 then the value of alpha for which Rolle's theorem can be applied in [0,1] is

If f(x)=x^alphalogx and f(0)=0 , then the value of alpha for which Rolle's theorem can be applied in [0,1] is

If f(x)=x^(alpha) logx and f(0)=0 , then the value of alpha for which Roll's theorem can be applied in [0, 1] is :

If f(x) = {:{(x^(alpha)logx,","xgt 0),(0,","x=0):} and Rolle' theorem is applicable to f(x) for x in [0,1] then alpha may be equal to

If f(x)={(x^(alpha)logx , x > 0),(0, x=0):} and Rolle's theorem is applicable to f(x) for x in [0, 1] then alpha may equal to (A) -2 (B) -1 (C) 0 (D) 1/2

If f(x)={(x^(alpha)logx , x > 0),(0, x=0):} and Rolle's theorem is applicable to f(x) for x in [0, 1] then alpha may equal to (A) -2 (B) -1 (C) 0 (D) 1/2

If f(x)={(x^(alpha)logx , x > 0),(0, x=0):} and Rolle's theorem is applicable to f(x) for x in [0, 1] then alpha may equal to (A) -2 (B) -1 (C) 0 (D) 1/2