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From 4 red balls, 2 white balls and 4 bl...

From 4 red balls, 2 white balls and 4 black balls, four balls are selected. The probability of getting 2 red balls is p, then the value of 7p

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1

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The correct Answer is:
To solve the problem, we need to calculate the probability \( p \) of selecting 2 red balls when we randomly select 4 balls from a total of 10 balls (4 red, 2 white, and 4 black). ### Step-by-Step Solution: 1. **Identify Total Balls**: We have: - 4 Red balls - 2 White balls - 4 Black balls - **Total = 4 + 2 + 4 = 10 balls** 2. **Determine the Required Selection**: We want to find the probability of selecting exactly 2 red balls when selecting 4 balls. This means we need to consider the other 2 balls which can be either white or black. 3. **Cases for the Remaining Balls**: The remaining 2 balls can be: - 2 White balls - 2 Black balls - 1 White and 1 Black ball 4. **Calculate Probabilities for Each Case**: We will calculate the probability for each case and then sum them up. - **Case 1**: 2 Red and 2 White \[ \text{Number of ways to choose 2 red from 4} = \binom{4}{2} = 6 \] \[ \text{Number of ways to choose 2 white from 2} = \binom{2}{2} = 1 \] \[ \text{Total for this case} = 6 \times 1 = 6 \] - **Case 2**: 2 Red and 2 Black \[ \text{Number of ways to choose 2 red from 4} = \binom{4}{2} = 6 \] \[ \text{Number of ways to choose 2 black from 4} = \binom{4}{2} = 6 \] \[ \text{Total for this case} = 6 \times 6 = 36 \] - **Case 3**: 2 Red, 1 White, and 1 Black \[ \text{Number of ways to choose 2 red from 4} = \binom{4}{2} = 6 \] \[ \text{Number of ways to choose 1 white from 2} = \binom{2}{1} = 2 \] \[ \text{Number of ways to choose 1 black from 4} = \binom{4}{1} = 4 \] \[ \text{Total for this case} = 6 \times 2 \times 4 = 48 \] 5. **Total Favorable Outcomes**: Now, we sum the outcomes from all cases: \[ \text{Total favorable outcomes} = 6 + 36 + 48 = 90 \] 6. **Total Possible Outcomes**: The total ways to choose any 4 balls from 10: \[ \text{Total outcomes} = \binom{10}{4} = \frac{10 \times 9 \times 8 \times 7}{4 \times 3 \times 2 \times 1} = 210 \] 7. **Calculate Probability \( p \)**: \[ p = \frac{\text{Total favorable outcomes}}{\text{Total outcomes}} = \frac{90}{210} = \frac{3}{7} \] 8. **Calculate \( 7p \)**: \[ 7p = 7 \times \frac{3}{7} = 3 \] ### Final Answer: The value of \( 7p \) is \( \boxed{3} \).
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