In a leap year find the probability of
(ii) 53 Mondays and 53 Wednesday

Answer

To solve the problem of finding the probability of having 53 Mondays and 53 Wednesdays in a leap year, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Structure of a Leap Year**:
- A leap year has 366 days.
- This means there are 52 complete weeks (which account for 52 x 7 = 364 days) and 2 extra days.

2. **Identify the Extra Days**:
- Since there are 2 extra days in a leap year, we need to determine what these two days could be.
- The days of the week are: Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, and Sunday.

3. **List Possible Combinations of Extra Days**:
- The possible combinations of the 2 extra days in a week are:
- Sunday and Monday
- Monday and Tuesday
- Tuesday and Wednesday
- Wednesday and Thursday
- Thursday and Friday
- Friday and Saturday
- Saturday and Sunday

4. **Determine Conditions for 53 Mondays and 53 Wednesdays**:
- For there to be 53 Mondays and 53 Wednesdays, one of the extra days must be a Monday and the other must be a Wednesday.
- However, looking at the combinations of extra days listed above, we can see that it is impossible to have both a Monday and a Wednesday as the extra days.

5. **Conclusion**:
- Since it is impossible to have both a Monday and a Wednesday as the extra days in a leap year, the scenario of having 53 Mondays and 53 Wednesdays cannot occur.
- Therefore, the probability of having 53 Mondays and 53 Wednesdays in a leap year is 0.

### Final Answer:
The probability of having 53 Mondays and 53 Wednesdays in a leap year is **0**.