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In a leap year find the probability of ...

In a leap year find the probability of
(iv) 53 Mondays or 53 Wednesday

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To solve the problem of finding the probability of having 53 Mondays or 53 Wednesdays in a leap year, we can follow these steps: ### Step 1: Understand the structure of a leap year A leap year has 366 days. This can be expressed as: \[ 366 = 52 \text{ weeks} + 2 \text{ extra days} \] Since there are 7 days in a week, each day of the week will occur 52 times in 52 weeks. ### Step 2: Determine the number of occurrences of each day In a leap year: - Each day of the week (Monday, Tuesday, Wednesday, etc.) occurs 52 times. - The remaining 2 days will determine whether there are 53 occurrences of a specific day. ### Step 3: Identify the possible combinations of the extra days The 2 extra days can be any combination of the days of the week. The possible pairs of extra days are: 1. Sunday and Monday 2. Monday and Tuesday 3. Tuesday and Wednesday 4. Wednesday and Thursday 5. Thursday and Friday 6. Friday and Saturday 7. Saturday and Sunday ### Step 4: Determine favorable outcomes for 53 Mondays or 53 Wednesdays To have 53 Mondays, one of the extra days must be a Monday. The combinations that include Monday are: - Sunday and Monday - Monday and Tuesday To have 53 Wednesdays, one of the extra days must be a Wednesday. The combinations that include Wednesday are: - Tuesday and Wednesday - Wednesday and Thursday ### Step 5: Count the favorable outcomes From the combinations: - For 53 Mondays: 2 favorable combinations (Sunday-Monday, Monday-Tuesday) - For 53 Wednesdays: 2 favorable combinations (Tuesday-Wednesday, Wednesday-Thursday) However, the combination of Sunday and Monday also counts towards 53 Mondays, and Tuesday and Wednesday counts towards 53 Wednesdays. Therefore, we need to ensure we do not double count: - Total unique favorable outcomes for 53 Mondays or 53 Wednesdays: 4 (Sunday-Monday, Monday-Tuesday, Tuesday-Wednesday, Wednesday-Thursday) ### Step 6: Calculate the total outcomes The total number of outcomes (combinations of 2 extra days) is 7. ### Step 7: Calculate the probability The probability of having either 53 Mondays or 53 Wednesdays is given by: \[ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total outcomes}} = \frac{4}{7} \] Thus, the final answer is: \[ \text{Probability of 53 Mondays or 53 Wednesdays} = \frac{4}{7} \] ---
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