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If A=[(x,0),(1,1)]andB=[(1,0),(5,1)] fin...

If `A=[(x,0),(1,1)]andB=[(1,0),(5,1)]` find x such that `A^(2)=B`.

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To solve the problem, we need to find the value of \( x \) such that \( A^2 = B \), where \[ A = \begin{pmatrix} x & 0 \\ 1 & 1 \end{pmatrix}, \quad B = \begin{pmatrix} 1 & 0 \\ 5 & 1 \end{pmatrix}. \] ### Step 1: Calculate \( A^2 \) To find \( A^2 \), we multiply matrix \( A \) by itself: \[ A^2 = A \cdot A = \begin{pmatrix} x & 0 \\ 1 & 1 \end{pmatrix} \cdot \begin{pmatrix} x & 0 \\ 1 & 1 \end{pmatrix}. \] ### Step 2: Perform the matrix multiplication Using the formula for matrix multiplication, we calculate each element of the resulting matrix: - The element at the first row, first column: \[ x \cdot x + 0 \cdot 1 = x^2. \] - The element at the first row, second column: \[ x \cdot 0 + 0 \cdot 1 = 0. \] - The element at the second row, first column: \[ 1 \cdot x + 1 \cdot 1 = x + 1. \] - The element at the second row, second column: \[ 1 \cdot 0 + 1 \cdot 1 = 1. \] Thus, we have: \[ A^2 = \begin{pmatrix} x^2 & 0 \\ x + 1 & 1 \end{pmatrix}. \] ### Step 3: Set \( A^2 \) equal to \( B \) Now we set \( A^2 \) equal to \( B \): \[ \begin{pmatrix} x^2 & 0 \\ x + 1 & 1 \end{pmatrix} = \begin{pmatrix} 1 & 0 \\ 5 & 1 \end{pmatrix}. \] ### Step 4: Create equations from the matrix equality From the equality of the matrices, we can create the following equations: 1. \( x^2 = 1 \) 2. \( 0 = 0 \) (This is always true and gives no information) 3. \( x + 1 = 5 \) 4. \( 1 = 1 \) (This is also always true) ### Step 5: Solve the equations From the first equation \( x^2 = 1 \): \[ x = 1 \quad \text{or} \quad x = -1. \] From the third equation \( x + 1 = 5 \): \[ x = 5 - 1 = 4. \] ### Step 6: Check for consistency We have two possible values for \( x \) from the first equation: \( x = 1 \) and \( x = -1 \). However, from the third equation, we found \( x = 4 \). Since we have conflicting values for \( x \), we conclude that there is no single value of \( x \) that satisfies both equations. ### Final Conclusion Thus, there is no such \( x \) that satisfies \( A^2 = B \). ---
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CBSE COMPLEMENTARY MATERIAL-MATRICES AND DETERMINANTS-TWO MARK QUESTIONS
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  8. If A=[(2),(3),(5)]andB=["1 2 3"], Verify (AB)'=B'A'

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  17. If A=[(x,0),(1,1)]andB=[(1,0),(5,1)] find x such that A^(2)=B.

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