Let `g(x)=int(1+2cosx)/((cosx+2)^2)dxa n dg(0)=0.` then the value of `8g(pi/2)` is __________

int_(0)^(pi//2) (1+ 2 cos x)/((2+ cosx )^(2) )dx =

int_(0)^( pi/2)(cosx/(cosx+sinx))dx

int_0^(pi/2) cosx/(1+sinx)dx

int_(0)^( pi/2)(cosx)/(1+sinx)dx

int_(0)^( pi/2)(cosx)/(1+sin x)dx

int_(0)^((pi)/2)(cos2x)/(cosx+sinx)dx=

Find the value of int_0^(2pi) |cosx|dx

8) int_0^(2pi)cosx dx

Let I_(n)=int_(0)^(pi//2)(sinx+cosx)^(n)dx(nge2) . Then the value of n. I_(n)-2(n-1)I_(n-1) is

If M=int_(0)^((pi)/2)(cosx)/(x+2)dx and N=int_(0)^((pi)/4)(sinxcosx)/((x+1)^(2))dx , then the value of M-N is