Area bounded by curve `y=sinx`, whit x-axis, when x varies from 0 to `(pi)/(2)` is :-

From the following figure, find the area of the region bounded by the curves y=sinx , y=cosx and x axis as x varies from 0 to pi/2

The area of the region bounded by the curve y=sin x , x- axis and the ordinates x=0 , x=(pi)/(3) is

The area (in square unit) bounded by the curve y= sec x, the x-axis and the lines x=0 and x=(pi)/(4) is-

The area bounded by the curve y=sin^(-1)(sinx) and the x - axis from x=0" to "x=4pi is equal to the area bounded by the curve y=cos^(-1)(cosx) and the x - axis from x=-pi " to "x=a , then the value of a is equal to

The area bounded by the curve y=sin^(-1)(sinx) and the x - axis from x=0" to "x=4pi is equal to the area bounded by the curve y=cos^(-1)(cosx) and the x - axis from x=-pi " to "x=a , then the value of a is equal to

Find the area bounded by the curve y= sin x with x-axis, between x=0 and x=2 pi

Area bounded by the curve y=x sin x and x -axis between x=0 and x=2 pi is :

The area bounded by the curve y =4 sin x, x-axis from x =0 to x = pi is equal to :

The area (in squnit) bounded by the curve y= sinx , x-axis and the two ordintes x= pi,x=2pi is