(sin theta+sin2 theta)/(1+cin6+cos26)=

(sin theta+sin2 theta)/(1+cos theta+cos2 theta)=tan theta=sin theta*sec theta

(sin theta+sin2 theta)/(1+cos theta+cos2 theta)=tan theta

(sin theta+sin2 theta)/(1+cos theta+cos2 theta)=tan theta

If sin theta + sin^(2) theta =1 then cos^(4) theta + cos^(8) theta + 2 cos^(6) theta =

Show that ((cos theta - cos 3theta)(sin 8theta + sin 2 theta))/((sin 5 theta - sin theta)(cos 4 theta - cos 6 theta)) = 1

Prove that ((cos theta-cos 3 theta)(sin 8 theta +sin 2 theta))/((sin 5 theta-sin theta)(cos 4 theta-cos 6 theta))=1

Show that ((cos theta - cos 3 theta) (sin 8 theta + sin 2 theta))/((sin 5 theta - sin theta) (cos 4 theta- cos 6 theta))=1

1- (sin ^ (2) theta) / (1 + cos theta) + (1 + cos theta) / (sin theta) - (sin theta) / (1-cos theta) - (1) / (sec theta)

(1 + cos theta + sin theta) / (1 + cos theta-sin theta) = (1 + sin theta) / (cos theta)

1-(sin^(2)theta)/(1+cos theta)+(1+cos theta)/(sin theta)-(sin theta)/(1-cos theta) equals