The function `f(x)=x/2+2/x` has a local minimum at `x=2` (b) `x=-2` `x=0` (d) `x=1`

The function f(x)=2x^3-3x^2-12x+5 has a minimum at x=

Show that f(x)=x^2+(250)/x has a local minimum at x=5.

The function f(x)=(x-1)^(2) has a minimum at x is equal to

The function f(x)=x^(2)e^(x) has minimum value

The function f(x)=2x^(3)-3(a+b)x^(2)+6abx has a local maximum at x=a , if

The function f(x)=(ax+b)/((x-1)(x-4)) has a local maxima at (2,-1), then

If the function f(x) = x^(2) + alpha//x has a local minimum at x=2, then the value of alpha is

The function f(x)=x(x+4)e^(-x/2) has its local maxima at x=a* Then (a)a=2sqrt(2)(b)a=1-sqrt(3)(c)a=-1+sqrt(3)(d)a=-4