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Suppose p is the first of n(n > 1) AM...

Suppose p is the first of n(n > 1) AM's between two positive numbers a and b, then value of p is (i)`(na+b)/(n+1)` (ii)`(na-b)/(n+1)` (iii)`(nb+a)/(n+1)` (iv) `(nb-a)/(n+1)`

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