Area bounded by `y=tan x, y=tan^2x` in between `x in (-pi/3,pi/3)` is equal to `(pi/4+lnsqrt(2)-1)`

The area bounded by y=tan x,y=cot x,x axis in 0<=x<=(pi)/(2) is

The area bounded by y = tan x, y = cot x, X-axis in 0 lt=x lt= pi/2 is

The area bounded by curves y = tan x, x-axis and x= pi/3 is-

The area bounded by the curve y=cosx and y=sin 2x, AA x in [(pi)/(6), (pi)/(2)] is equal to

The area bounded by the curve y=cosx and y=sin 2x, AA x in [(pi)/(6), (pi)/(2)] is equal to

What is the area bounded by y = tan x, y = 0 and x =pi/4 ?

If y = tan x, then at x = pi/2 , y_2 is equal to

The area bounded by the curve y=sin x between x=(pi)/(2) and x=(3 pi)/(2)

Area bounded by curve y= tan pi x , x in [-1/4 ,1/4] and X-axis is …..

Area bounded by the curve y=max{sin x, cos x} and x -axis, between the lines x=(pi)/(4) and x=2 pi is equal to