`int(x^2+x-1)/(x^2+x-6)dx`

int(x^6+1)/(x^2+1)dx

Evaluate the integrals int(x^6 + 1)/(x^2 + 1) dx

int(x+1)/(x^2+5x+6)dx=

int (x^(2) + x -1)/(x^(3) + x^(2) - 6x)dx

(i) int((x^(2) - 1)/(x^(2) + 1))dx , (ii) int ((x^(6)- 1)/(x^(2) + 1))dx (iii) int ((x^(4))/(1+x^(2)))dx , (iv) int((x^(2))/(1+x^(2)))dx

6. int(1-x^2)/(x-2x^3)dx

int (dx)/((x+1)(2x+1)) (ii) int (x-1)/((x-2)(x-3)) dx .

int (x^(6) - 1)/(x^(2) +1) dx =

int (x ^(2) + x-6)/((x -2) (x -1))dx = x + ...................+ c

int(x^(2))/(1+x^(6)) dx