If `cosA=mcosB,` then `cot((A+B)/2)=(m+1)/(m-1) tan((B-A)/2)`

If cos A=m cos B, then cot((A+B)/(2))=(m+1)/(m-1)tan((B-A)/(2))

If cos A=m cos B, then (1)cot((A+B)/(2))=(m+1)/(m-1)*tan((B-A)/(2))(2)tan((A+B)/(2))=(m+1)/(m-1)*cot((A-A)/(2))(3)cot((A+B)/(2))=(m+1)/(m-1)*tan((A-A)/(2))(4)tan((A-B)/(2))=(m+1)/(m-1)*cot((B-A)/(2))

If cos A=m cos B then prove that cot((A+B)/(2))=(m+1)/(m-1)tan((B-A)/(2))

If cos A=m cos B then prove that cot((A+B)/(2))=(m+1)/(m-1)tan((B-A)/(2))

if cosA=m cos B and cot((A+B)/(2))=lamda . tan((B-A)/(2)) then lamda is equal to

Sin A=m sin B,show that , tan((A-B)/2)=(m-1)/(m+1)tan((A+B)/2)

If cos A=mcosB ,\ t h e ncot((A+B)/2)cot((B-A)/2) adot\ (m-1)/(m+1) b. (m+2)/(m-2) c. (m+1)/(m-1) d. none of these

If cos A = m cos B, then prove that cot frac (A+B)(2)= (m+1)/(m-1) tan ((B-A)/2) .

If quad cos A=m cos B, then (cot(A+B))/(2)(cos(B-A))/(2)a*(m-1)/(m+1) b.(m+2)/(m-2) c.(m+1)/(m-1)d .none of these

If cosA=mcosB , then ............. A) cot ((A+B)/(2)) =(m+1)/(m-1) tan ((B-A)/(2)) B) tan ((A+B)/(2)) =(m+1)/(m-1) cot ((B-1)/(2)) C) cot ((A+B)/(2)) =(m+1)/(m-1) cot ((B-A)/(2)) D) None of these