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If 2s=a+b+c and A=|[a^2,(s-a)^2,(s-a)^2]...

If `2s=a+b+c and A=|[a^2,(s-a)^2,(s-a)^2],[(s-b)^2,b^2,(s-b)^2],[(s-c)^2,(s-c)^2,c^2]|` then det A

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