The molar conductivity of a `0.5 mol//dm^(3)` solution of `AgNO_(3)` with electrolytic conductivity of `5.76 xx 10^(-3) S cm^(-1)` at `298 K` is

Options

A. `2.88 S cm^(2)//mol`
B. `11.52 S cm^(2)//mol`
C. `0.086 S cm^(2)//mol`
D. `28.8 S cm^(2)//mol`

Answer

B

Explanation

(b) Key Idea The realtion between molar conductivity `(lambda_(m))` and electrolytic conductivity (k) is given as
`lambda_(m)=(kxx1000)/(m)`
where, M is molarity of solution.
Given, concentration of solution,
`M=0.5 mol//dm^(3)`
Electrolytic conductivity,
`k=5.76xx10^(-3) S cm^(-1)`
Temperature , T=298 K
`:.` Molar conductivity ,
`lambda_(m)=(kxx1000)/(M)=(5.76xx10^(-3)xx1000)/(0.5)`
`=11.52 S cm^(2)//mol`