A hydrogen gas electrode is made by dipping platinum wire in a solution of `HCl` or `pH = 10` and by passing bydrogen gas around the platinum wire at one atm pressure . The oxidation potential of electrode would be ?

Options

A. 0.059 V
B. 0.59 V
C. 0.118 V
D. 1.18 V

Answer

B

Explanation

(b) For hydrogent electrode, oxidation half reaction is
`underset((1 atm))(H_(2)) to underset(" (At pH 10)")(2H^(+))+2e^(-)`
If pH=10
`H^(+)=1xx10^(-pH)=1xx10^(-10)`
From Nernst equation,
`E_(cell) =E_(cell)^(@)-(0.0591)/(2)log""([H^(+)]^(2))/(p_(H_(2)))`
For hydrogen electrode, `E_(cell)^(@)=0`
`E_(cell)-(0.0591)/(2) log""((10^(-10))^(2))/(1)`
`=+(0.0591xx1)/(2) log""(1)/(10^(-10))`
`=0.0591 log 10^(10)=0.0591xx10=0.591 V`